Question

please help me match the line described on the left with the slope of the line on the right. thankyou!!

Answer 1

We have:

* y = 3, Horizontal straight lines have zero slope, since the "rise" is zero.

Answer: 0

* 9x - 3y = 18, We rearrange to the slope form equation, which is: y = mx + b, so:

`\begin{gathered} 9x-3y-9x=18-9x \\ -3y=18-9x \\ (-3y)/(-3)=(18)/(-3)-(9x)/(-3) \\ y=3x+6 \end{gathered}`

So the slope is 3.

Answer: 3

* (5,7) and (5, -8) the slope is given by the formula:

`m=(y2-y1)/(x2-x1)=(-8-7)/(5-5)=(-15)/(0)`

So, the "run" is zero, and division by zero is not allowed.

Answer: undefined

* (-4, -1) and (-1, -7)

`m=(-7-(-1))/(-1-(-4))=(-7+1)/(-1+4)=-(6)/(3)=-2`

Answer: - 2