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Factoring a quadratic with leading coefficient greater than 1: Problem type 1

Factoring a quadratic with leading coefficient greater than 1: Problem type 1-example-1
User PeteUK
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1 Answer

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27 votes

My Land, this is the solution:

Step 1: Let's factor the quadratic equation:

2z² + 19z - 21

(2z - 2 ) (z + 10.5) = 0

These are the operations to show it works:

2z * z = 2z²

2z * 10.5 - 2 * z = 21z - 2z = 19z

-10.5 * 2 = -21

Thus, the factors are right.

Step 2: Now, let's calculate the roots of the equation, as follows:

First root:

2z - 2 = 0

Dividing by 2:

z - 1 = 0

z1 = 1

Second root:

z + 10.5 = 0

z2 = -10.5

• The factors are (2z - 2) and (z + 10.5)

,

• The roots are -10.5 and 1

User GreenScape
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