Question

Find and graph a 2nd degree polynomial function whose graph contains the point (0,-9)

Answer 1

Okay, here we have this:

Considering the provided information, we are going to find the requested polynomial function, so we obtain the following:

Then let us remember that a second degree polynomial has the following form:

f(x)=ax^2+bx+c, where a, b and c are integers.

So replacing with the given point we get:

-9=a(0)^2+b(0)+c

-9=0+0+c

-9=c

Therefore any polynomial of the form ax^2+bx+c with c=-9 will pass through the given point, so if we take for example a=1, b=1 and c=-9, we obtain the following graph:

f(x)=1x^2+1x-9: