Question

Resistors of values 6.0Ω, 4.0Ω, 10.0Ω and 7.0Ω are combined as shown. What is the equivalent resistance for this combination? Answer: _________ Ω

Answer 1

`10.67Ω`

Step-by-step explanation

First, we have to find the total resistance for the 4Ω and 10Ω resistors connected in series.

To do this, find the sum of the resistances:

`4+10=14Ω`

This total resistance is connected in parallel to the 7Ω resistor. Find the total resistance of the two of them:

`\begin{gathered} (1)/((1)/(14)+(1)/(7)) \\ \\ (1)/((3)/(14))=(14)/(3) \\ \\ 4.67Ω \end{gathered}`

The equivalent resistance is the total resistance of the 6Ω resistor and the 4.67Ω resistance. Since they are connected in series, find the sum:

`\begin{gathered} 6+4.67 \\ \\ 10.67Ω \end{gathered}`

That is the equivalent resistance.