Question

Question 1 of 10How many moles of ammonia would be required to react exactly with0.876 moles of copper(ll) oxide in the following chemical reaction?2 NH (g) + 3 CuO(s) – 3 Cu(s) + N,(g) + 3 H Og)

Answer 1

Given the balanced equation:

• 2 NH₃(g) + 3 CuO(s) → 3 Cu(s) + N₂(g) + 3 H₂O(g)

0. The coefficients tell you the mole ratios, so 2 moles ammonia (NH3) will react with 3 moles of copper(II) oxide, (CuO).

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1. We will set up a simple proportion in order to solve this , as follows:

• 2 mol NH3/3 mol CuO = x mol NH3/0.876mol CuO.

→0.876molCuO * 2molNH3/3molCuO=0.584 molesNH3

• This means that 0.584 moles of Ammonia, would be required to react exactly with 0.876 moles of copper(II) oxide.