Answer:
Step-by-step explanation:
a)
we need to find the horizontal range of the projectile
the formula for horizontal range is x = (u² sin2α)/g
= (255² × sin(2 × 73.7))/9.81
= 3571.2 m
Distance between ship and enemy ship = 2460 + 601 = 3061 m
So the projectile lands (3571.2 - 3061) = 510.2 m away from the enemy ship
b)
The peak is situated at 2460 m from the projectile.
The time required to reach the peak needs to be found out so that we can calculate the vertical displacement in that time.
To reach 2460 m time needed is x = u × cosα × t
⇒ 2460 = 255 × cos(73.7)° × t
⇒ t = 34.37s
Now, vertical displacement after 34.37s is
y = (u × sinα × t) - (1/2 × g × t²)
= (255 × sin(73.7) × 34.37) - (1/2 × 9.81 × (34.37)²)
=2617.81 m
The peak is 1760m high
So the projectile comes (2617.81 - 1760) = 857.8m away from the peak
If you need notes on this, I could send you my pdf on this one cause I'm not sure if I explained why I used which formula