Question

Which of the numbers 2, 3, 4, 6 and 9 are factors of 1881?

Answer 1

since 1881 is an odd number, dividing it by an even number will leave you with a remainder, so 2, 4, and 6 are automatically excluded

1881/3 = 627
1881/9 = 209

so both 3 and 9 are factors

Answer 2

`1881|3\\.\ 627|3\\.\ 209|11\\.\ \ 19|19\\.\ \ \ 1|\\\\1881=3*3*11*19\\\\Your\ answer:\boxed{3;\ 3*3=9}`