Question

During the winter, a competitive bike rider trains on a stationary bike. Her trainer wants her to warm up for 5 to 10 minutes by pedaling slowly. Then she is to increase the pace to 95 revolutions per minute for 30 seconds. Through how many degrees will a point on the outside of the tire travel during the 30 seconds of the faster pace?

Answer 1

Well I don't know.
Let's see:

-- 1 minute = 60 seconds, so 30 seconds = 1/2 of a minute.

-- If she's pedaling at a rate of 95 revolutions per minute, then
she'll make (95/2) = 47.5 revolutions during the 1/2 minute.

-- Each revolution is 360 degrees.

-- 47.5 revolutions = (47.5 x 360 degrees) = 17,100 degrees