Question

Solve for n: 21k – 3n + 9p > 3p + 12.

A.n > 2p + 7k - 4

B.n < 2p + 7k - 4

C. n > -4p - 7k + 4

D. n < -4p - 7k + 4

Answer 1

solve for n.21k−3n+9p>3p+12Add -21k to both sides.21k−3n+9p+−21k>3p+12+−21k−3n+9p>−21k+3p+12Add -9p to both sides.−3n+9p+−9p>−21k+3p+12+−9p−3n>−21k−6p+12Divide both sides by -3.−3n/−3 > −21k−6p+12/−3n < 7k+2p−4

ANSWER IS B

Answer 2

solve for n.

21k−3n+9p>3p+12

Add -21k to both sides.

21k−3n+9p+−21k>3p+12+−21k

−3n+9p>−21k+3p+12

Add -9p to both sides.

−3n+9p+−9p>−21k+3p+12+−9p

−3n>−21k−6p+12

Divide both sides by -3.

−3n/−3 > −21k−6p+12/−3

n < 7k+2p−4


`\huge{\boxed{\boxed{\boxed{\boxed{\hbox{So your answer is B.}}}}}}`