Question

5log625+25log625+625log625

Answer 1

`loc_c(a^m)=mlog_ca \\log_ca+log_cb=log_c(a * b) \\ a^x * a^y=a^(x+y)\\ \\ 5^2=25 \\ 5^4=625 \\ \\ 5log625+25log625+625log625= \\ log(625^5)+log(625^(25))+log(625^(625))= \\ log(5^(4 * 5)) + log(5^(4 * 25)) + log(5^(4 * 625)) = \\ log5^(20)+log5^(100)+log5^(2500)= \\ log(5^(20)*5 ^(100) * 5^(2500))= \\ log5^(20+100+2500)= \\ log5^(2620)= \\ 2620log5`