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3 votes
Determine the nature of the roots: 3x^2+12x-3=0

two distinct real solutions

c.

no real solutions
b.

cannot be determined

d.

a unique real solution

User Xyon
by
7.5k points

2 Answers

3 votes

Answer:

The answer is C)

two distinct real solutions

Explanation:

On edge 2021

User Sergey Bespalov
by
7.4k points
4 votes
The roots of a quadratic equation ax²+bx+c=0 can be determined by calculating the discriminant Δ=b²-4ac.
If Δ>0, there are two distinct real solutions.
If Δ=0, there is one real solution.
If Δ<0, there are no real solutions and two complex solutions.


3x^2+12x-3=0 \\ \\ a=3 \\ b=12 \\ c=-3 \\ \\ \Delta=b^2-4ac=12^2-4 * 3 * (-3)=144+36=180

Δ>0, so there are two distinct real solutions. The answer is A.
User TimChang
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8.0k points