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A pitcher supplies a power of P = 227 W to a baseball of mass m = 0.095 kg for a period of t = 0.25 s. what is 5the balls speed in meter per second?

User Chiefir
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1 Answer

19 votes
19 votes

Given data

*The given power is P = 227 W

*The given mass of the baseball is m = 0.095 kg

*The given time is t = 0.25 s

The formula for the relation between the power, energy, and time is given as


P=(E)/(t)

Substitute the known values in the above expression as


\begin{gathered} 227=(E)/(0.25) \\ E=56.75\text{ J} \end{gathered}

The formula for the ball speed is given by using the energy relation as


E=(1)/(2)mv^2

Substitute the known values in the above expression as


\begin{gathered} 56.75=(1)/(2)(0.095)v^2 \\ v=34.5\text{ m/s} \end{gathered}

Hence, the speed of the ball is v = 34.5 m/s

User Oxfist
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