Final answer:
The molar solubility of cobalt(II) hydroxide is approximately 1.44 × 10-5 M.
Step-by-step explanation:
The molar solubility of a compound can be calculated using the solubility product constant (Ksp). The Ksp of cobalt(II) hydroxide, Co(OH)2, is provided as 5.92 × 10-15. Since Co(OH)2 dissociates into Co²⁺ ions and OH⁻ ions, and the stoichiometry of the reaction is 1:2, the equilibrium concentration of Co²⁺ ions and OH⁻ ions will be 2x and x, respectively. Therefore, we can set up the expression for the Ksp: Ksp = [Co²⁺][OH⁻]² = (2x)(x)² = 5.92 × 10-15.
Simplifying this equation, we get x³ = 2.96 × 10-15. Taking the cube root of both sides, we find that the molar solubility of Co(OH)2 is approximately 1.44 × 10-5 M.