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1.7.3 Quiz Build a Chart and Find a Pattern Pierre traveled down a canal by barge from the town of Portage (elevation 767 feet) to the town of Barrage (elevation 642 feet). On the way, he had to pass through a series of locks. If each lock lowered the barge 25 feet, how many locks did he pass through?

User AbSiddique
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1 Answer

27 votes
27 votes

We have the following information:

We have that each lock lowered the barge 25 feet.

Then, because the amount that the barge lowers the canal is constant (it is the same), we can calculate the number of locks as follows:


NL=(767-642)/(25)=(125)/(25)\Rightarrow NL=5

Then, the number of locks is 5 (this is the answer).

We can check this result as follows:

In the first lock, the barge lowers 25 feet, in the second, another 25 feet, in the third, 25 feet, and so on. It happens 5 times. Then, the total is 5 * 25 = 125 feet. If we subtract this value from 767 feet, we finally obtain the elevation of the barge at the Town of Barrage (642 feet). That is:


767ft-125ft=642ft

1.7.3 Quiz Build a Chart and Find a Pattern Pierre traveled down a canal by barge-example-1
User Partha
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