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How many milliliters of a 3.0 M HCl solution are required to make 250.0 milliliters of 1.2 M HCl?

2 Answers

4 votes
M1V1=M2V2
(3)(V1)=(250)(1.2)
V1=100 mL
User Erik Noren
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0 votes
The formula to use is M₁V₁=M₂V₂
We are trying to find V₁ so V₁=M₂V₂/M₁
=250X1.2 /3
=100mL
User Atcold
by
7.3k points

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