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Find y intercept of the line x+3y=-18

User P Jones
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1 Answer

8 votes
8 votes

Recall that the slope-intercept form of the equation of a line is as follows:


y=mx+b,

where m is the slope of the line and (0,b) is the y-intercept.

Substracting x from the given equation we get:


\begin{gathered} x+3y-x=-18-x, \\ 3y=-x-18. \end{gathered}

Dividing the above equation by 3 we get:


(3y)/(3)=(-x-18)/(3).

Therefore:


y=-(1)/(3)x-6.

Then the slope of the given equation is -1/3 and its y-intercept is (0,-6).

Answer: The y-intercept is


(0,-6).

The slope is:


-(1)/(3).

User Cosmin Onea
by
3.0k points
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