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19 votes
19 votes
A worm cancrawl 6 feet 8inches in 1 1/2hour. What is theworm's unitrate?

User Anil Meena
by
2.2k points

1 Answer

7 votes
7 votes

This problem involves proportions and also different units of measure.

So, first, let's write the distance the worm can crawl in 1 1/2 hour using inches.

We know that 1 foot = 12 inches. So, we have:

6 feet 8 inches = 6 * 12 inches + 8 inches

= 72 inches + 8 inches

= 80 inches

Also, notice that:

1 1/2 hour = (1 + 1/2) hour = 1.5 hour

Now, we have the proportions:

distance (in inches) time (in hour)

80 1.5

x 1

Now, we cross multiply those values to find:

1 * 80 = 1.5 * x

80 = 1.5 x

80/1.5 = 1.5x/1.5

80/1.5 = x

x = 80/1.5

x ≅ 53.33

So, we found that the worm can crawl approximately 53.33 inches per hour.

If we want to know its rate in feet per hour, we need to divide the result by 12:

1 foot = 12 inches

1/12 foot = 1 inch

53.33 inches = 53.33 (1/12 foot)

= (53.33/12) feet

≅ 4.44 feet

Therefore, the worm's rate is approximately 4.44 feet per hour.

User Comocomocomocomo
by
2.9k points
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