Alicia has 10 paintings she wants to hang side by side on her wall. if she only wants to display 3 of the paintings, how many ways can she choose to display the paintings? show your work.

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Bharani asked Aug 7, 2023

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Alicia has 10 paintings she wants to hang side by side on her wall. if she only wants to display 3 of the paintings, how many ways can she choose to display the paintings? show your work.

Mathematics
college

Bharani asked Aug 7, 2023

by Bharani

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The number of ways she can choose to display the paintings is given by:

$(10!)/((10-3)!)=(10!)/(7!)=10\cdot9\cdot8=720$

Medik answered Aug 13, 2023

by Medik

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