Question

what steps of the equation of the line using point slope formula then using slope intercept form (1,2) with slope of -6/7

Answer 1

`\begin{gathered} \text{ The point-slope form} \\ y-2=-(6)/(7)\cdot(x-1) \\ \text{ The slope-intercept form} \\ y=-(6)/(7)x+(20)/(7) \end{gathered}`

Explanation:

We have that the equation of the line in its point and slope form is the following:

`y-y_1=m\cdot(x-x_1)`

We replace and the equation would be like this:

`y-2=-(6)/(7)\cdot(x-1)`

We have that the equation of the line in its slope intercept form has the following form:

`y=mx+b`

So what we have is to solve for y, like this:

`\begin{gathered} y=-(6)/(7)x+(6)/(7)+2 \\ y=-(6)/(7)x+(6)/(7)+(14)/(7) \\ y=-(6)/(7)x+(20)/(7) \end{gathered}`