Question

If DA is a diameter of OZ and m/DZC = (2x)°, find m/CZB.A. 22°B. 58°C. 69°D. 73°

Answer 1

Since DA is the diameter the formed angle equals 180

since DZC=2x

then

`180=DZC+CZB+BZA`
`180=(2x)+(7x-4)+85`
`180-85+4=9x`
`x=(99)/(9)`
`x=11`

since x= 11

then the measure of the angle CZB is given by

`7(11)-4`
`mCZB=73`

measure of the angle CZB is 73°

Correct answer option D

73°