Question

Solve for x. Enter the solutions from least to greatest.4x^2 + 48x + 128 = 0lesser x = [ ]greater x = [ ]

Answer 1

Let's begin by identifying key information given to us:

`\begin{gathered} 4x^2+48x+128=0 \\ \text{Divide through by ''4'', we have:} \\ (4)/(4)x^2+(48)/(4)x+(128)/(4)=(0)/(4) \\ x^2+12x+32=0 \\ x^2+8x+4x+32=0 \\ \text{Factorising we have:} \\ x(x+8)+4(x+8)=0 \\ (x+8)(x+4)=0 \\ \Rightarrow x+8=0,x+4=0 \\ \Rightarrow x=-8,x=-4 \\ \\ \end{gathered}`

Lesser x = -8

Greater x = -4