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30 votes
30 votes
Maria is running a 20-kg race .the graph at the right shows her distance remaining and the race in kilograms over time and hours find a rate of changing for distance remaining during the race

Maria is running a 20-kg race .the graph at the right shows her distance remaining-example-1
User Peter Boone
by
2.8k points

1 Answer

19 votes
19 votes

Answer:

-5/2 km/hr

Step-by-step explanation:

We can find the rate of change for the distance remaining over time at points (2, 15) and (8, 0) using the below formula;


\text{Rate of Change = }(y_2-y_1)/(x_2-x_1)

where our x1 = 2, y1 = 15, x2 = 8, and y2 = 0.

Let's go ahead and substitute these values into our formula;


\begin{gathered} \text{Rate of Change = }(0-15)/(8-2) \\ =(-15)/(6) \\ =-(5)/(2) \end{gathered}

So this means that the distance decreases by 5km in every 2hours.

User Neha Kumari
by
2.7k points
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