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Use the circle unit to evaluate cos(23/6)

User Maurice Naftalin
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1 Answer

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23 votes

Given


\begin{gathered} \cos \text{ }(23\pi)/(6) \\ A\text{ complete revolution in a circle is 2}\pi \\ We\text{ have to re-write }(23\pi)/(6)\text{ in such a way that it will not be more than 2}\pi\text{ } \\ \text{Hence, } \\ cos(23\pi)/(6)\text{ = cos(}(23\pi)/(6)-(24\pi)/(6)) \\ \cos \text{(}(23\pi)/(6))\text{ = cos(}(-\pi)/(6)) \end{gathered}

The representation on the unit circle is shown below

Going round the circle in the negative direction, we realize


\cos ((-\pi)/(6))\text{ = cos(}(11\pi)/(6))\text{ = }\frac{\sqrt[]{3}}{2}
\text{The answer is }\frac{\sqrt[]{3}}{2}

Use the circle unit to evaluate cos(23/6)-example-1
User McMa
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