Question

1, This element has a complete outermost energy level and is found in the 5th period.

2. This element has 2 electrons it its outermost energy level and belongs to the 2nd period.
3. This element has 3 electrons in its Lewis dot structure and is in the 3p orbital section.
4. This element has 74 protons.
5.This element in the 4th period wants to gain one electron to make an ionic bond.
6. This element is the halogen in the 5th period.
7. This metalloid has 3 electrons in its 5p orbitals.
8. This element in the 5th period wants to lose two electrons to make an ionic bond.
9. This malleable metal has an atomic number of 47.
10.This element in the 2nd period will form an ionic compound with a 1:1 atom ratio with Magnesium.
11.This element has an electron configuration of 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p4.
12. This element was named for the scientist who discovered the nucleus of the atom using gold foil.
13. This noble gas belongs to the 6th period.
14. This element has 1 electron in its 4d orbital section.
15. This 3rd period element will not form compounds because it fits the Octet Rule.

Answer 1

Fluorine is the element that matches the given descriptions.

Step-by-step explanation:

The element that matches the given description is Fluorine. Fluorine is found in the 2nd period and belongs to Group 7A, which means it has 7 electrons in its outermost energy level. The element with 3 electrons in the Lewis dot structure and in the 3p orbital section is Boron. The element with 74 protons is Tungsten. The element in the 4th period that wants to gain one electron is Chlorine. The halogen in the 5th period is Iodine. The metalloid with 3 electrons in the 5p orbitals is Antimony. The element in the 5th period that wants to lose two electrons is Selenium. The malleable metal with an atomic number of 47 is Silver. The element in the 2nd period that forms an ionic compound with a 1:1 atom ratio with Magnesium is Fluorine. The element with the given electron configuration is Xenon. The element named after the scientist who discovered the nucleus of the atom using gold foil is Rutherfordium. The noble gas that belongs to the 6th period is Radon. The element with 1 electron in its 4d orbital section is Palladium. The 3rd period element that fits the Octet Rule and does not form compounds is Argon.

Answer 2

1) Xenon
2) Berylium
3) Aluminium (Assuming 3p = 3rd Period)
4) Tungsten
5) Bromine
6) Xenon again
7) Indium I think
8) Strontium
9) Titanium
10) Oxygen
11) I don't understand that at all XD
12) Rutherfordium
13) Radon
14) Potassium?
15) Argon

So somebody needs to confirm 3, 7, 11, and 14, but I think the rest are correct if you load up a Periodic table