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Solve for b in the following equation:3x + 3b = 12A.b = 12 - xB.b= 12 - 3xC.b=4 - xD.b=4 - 3x

User Edelin
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1 Answer

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3x + 3b = 12

Subtract 3x from both sides of the equation:

3x-3x+3b=12

3b=12-3x

Divide both sides by 3:

3b/3 = (12-3x)/3

b= 4-x

User Naftali
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