Question

How do I identify the slope and y-intercept of the line 17x-5y=25

Answer 1

Recall that the equation of a line in slope-intercept form is as follows:

`y=mx+b,`

where m is the slope of the line and (0,b) is its y-intercept.

Adding 5y-25 to the given equation we get:

`\begin{gathered} 17x-5y+5y-25=25+5y-25, \\ 17x-25=5y. \end{gathered}`

Dividing the above equation by 5 we get:

`\begin{gathered} (17x-25)/(5)=(5y)/(5), \\ (17)/(5)x-5=y. \end{gathered}`

Then:

`y=(17)/(5)x+(-5).`

Therefore the slope of the given line is 17/5 and its y-intercept is (0,-5).

Answer:

`\begin{gathered} Slope:(17)/(5), \\ y-intercept:(0,-5). \end{gathered}`