Question

Aparachutist's speed during a free fall reaches 55 meters per second. What is this speed in feet per second? At this speed, how many feet will the parachutistfall during 15 seconds of free fall? In your computations, assume that 1 meter is equal to 3.3 feet. Do not round your answers

Answer 1

Part A:

The parachutist's speed is 55 m/s.

This means he covers 55m distance in every second

To convert this 55m distance to feet,

`\begin{gathered} 1m=3.3ft \\ 55m=55*3.3 \\ =181.5ft \end{gathered}`

The speed will be a distance of 181 feet covered every second.

Hence, the speed in feet per second is;

`181.5ft\text{ per second}`

Part B:

The distance covered by the parachutist during 15 seconds of free fall will be;

Given:

`\begin{gathered} \text{speed, s = 181.5 ft per second} \\ t=15\text{seconds} \\ distance,d=\text{?} \\ \text{speed = }\frac{dis\tan ce}{\text{time}} \\ \text{distance = spe}ed\text{ }* time \\ d=181.5*15 \\ d=2722.5ft \end{gathered}`

Therefore, the parachutist fell 2722.5 feet in 15seconds during free fall.