Question

Solve for the two possible values of X: (3x – 14) (8x + 13) = 0

Answer 1

Since the right side is 0, so equate each factor by 0 and find the values of x

Put 3x - 14 = 0 and 8x + 13 = 0

3x - 14 = 0

Add 14 to both sides

3x - 14 + 14 = 0 + 14

3x = 14

Divide both sides by 3

`(3x)/(3)=(14)/(3)`
`x=(14)/(3)`

This is the first value of x

Let us do the same with other factor

8x + 13 = 0

Subtract 13 from both sides

8x + 13 - 13 = 0 - 13

8x = - 13

Divide both sides by 8

`(8x)/(8)=-(13)/(8)`
`x=-(13)/(8)`

This is the second value of x

So the two values of x are

`(14)/(3),-(13)/(8)`