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In DGE, DG = 8, GE = 17, and DE = 15. What is the length of DF? Round to the nearest hundred

In DGE, DG = 8, GE = 17, and DE = 15. What is the length of DF? Round to the nearest-example-1
User Sander Roest
by
2.3k points

1 Answer

22 votes
22 votes

Answer:

7.06 units

Step-by-step explanation:

The given side lengths are indicated in the diagram below:

Using similar triangles, we have:


\begin{gathered} (GF)/(8)=(8)/(17) \\ 17GF=64 \\ GF=(64)/(17) \\ GF=3.76 \end{gathered}

Next, apply Pythagorean Theorem to triangle DGF.


\begin{gathered} DG^2=DF^2+GF^2 \\ 8^2=DF^2+3.76^2 \\ DF^2=8^2-3.76^2 \\ DF^2=49.8624 \\ DF^{}=√(49.8624) \\ DF\approx7.06\text{ units} \end{gathered}

The length of DF is approximately 7.06 units (to the nearest hundred).

In DGE, DG = 8, GE = 17, and DE = 15. What is the length of DF? Round to the nearest-example-1
User Izzy Rodriguez
by
2.8k points