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Point P lies on the line with the equation y-4=3(x-2). If the x-coordinate of P is 4, what is the y-coordinate of P

User Cxa
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Let's start by tidying up that equation and put it into slope-intercept form (y = mx + b); from there, we can plug in coordinates.


y - 4 = 3(x-2)

Let's use the distributive property on the right side:

y - 4= 3x - 6

Now add 4 to both sides

(y - 4) + 4 = (3x - 6) + 4

Which simplifies to:

y = 3x - 2

Since that's the equation of our line, now we can plug in coordinates and see what it churns out.

We know that the x-coordinate of P = 4 so let's substitute 4 in for x and calculate the y-coordinate:


y = 3(4) - 2

y = 12 - 2

y = 10

So the y-coordinate for point P = 10
User Adam Florin
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