Question

An aircraft on it's take-off run has a steady acceleration of 3m/s^2. How much velocity does it gain 10 seconds?

Answer 1

To solve this, let's use the formula a=(v''-v')÷(t)

3=(v''-0)÷(10)
3=v÷10

Now isolate for velocity

v"=(3)(10)
v"=30 m/s!

Answer 2

Acceleration measures how fast the speed changes over time.

So, over 10s, the aircraft's speed changes by 3
`(m)/( s^(2) )` * 10s

So, the change is 30
`(m)/(s)`

Note that the one of the second units cancels out in the answer.