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5 votes
System of Equations

y=-x-1
y+x=3

Solve?

User Lexual
by
8.2k points

1 Answer

6 votes
Solve by substitution


\sf{y=-x-1}

\sf{y+x=3}

Just plug in y=-x-1 into y+x=3

So we get:


\sf{(-x-1)+x=3}

Simplify that:


\sf{-1=3}

And since that is not true, that means this system of equations has no solutions!
User Caritos
by
8.2k points