Question

At the end of the wedding. the bride threw the bouquet at 2 km at a speed of 13 m/s. How long did the bouquet remain in the air? DON'T FORGET YOUR UNITS! HINT: MAKE SURE THEY MATCH!!!

Answer 1

The formula for the speed is

`S=(d)/(t)`

Where S is the speed, d is the distance travelled, and t is the time taken

On rearranging it,

`t=(d)/(S)`

In the question, the speed is given in the unit m/s. And the distance is given in km. Before solving we have to change the units of all the quantities to SI units

Therefore,

`d=2\text{ km=2000 m}`

On substituting all the known values into the equation,

`t=(2000)/(13)=153.85\text{ s}`

Therefore the bouquet remained in the air for 153.85 s.