How many moles are in 5.68 g of ferric oxide? (Fe2O3)

Allen Qin asked Jan 19, 2023

456,273 views

45 votes

Allen Qin asked Jan 19, 2023

2.7k points

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

19 votes

Answer:

0.036 mole

Step-by-step explanation:

Fe = 55.845 g

O = 16 g

Fe2O3 = 2(55.845) + 3(16) = 159.69 g

1 mole of Fe2O3 has 159.69 g

so the #mole of 5.68 g = (1 x 5.68)/159.69 = 0.036

Jovik answered Jan 25, 2023

by Jovik

2.7k points

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers