ANSWER:
Given following piecewise functions (Defined on more than one intervals).
![h(x)\text{ =}\begin{cases}x^2-1\text{ , x }\leq-1\text{ } \\ 4,\text{ -1 }We will evaluate these functions in order as <strong>f(x)</strong> , <strong>g(x)</strong> and finally<strong> h(x). </strong><p>Next these functions will be evaluated.</p>[tex]\begin{gathered} f(-(7)/(2))=-5 \\ g(4)=-3 \\ h(-(1)/(2))=-(1)/(2) \end{gathered}]()
NOTE! To evaluate h(x) at given x, we were required to evaluate g(x) at the same x value.
This is the result of evaluating three piecewise functions at specified x values, as it was asked in the question.!