The vertex and the x-intercepts of the quadratic function g(x)=x^2+4x-12
The quadratic function g(x)=x^2+4x-12 is a parabola y = ax^2+bx+c
To find the vertex of a parabola you can use the expression,
Vertex (x,y) = (-b/(4a), (-b^2/ 4a)+c )
x= -b/4a
y= (- (b^2)/ 4a)+c
Replacing
Vertex (x,y) = (2, -16)
The X intercept x= 0; y = -12
So then, the vertex is (2, -16), and the x-intercept (0, 12)