Question

Write an equation of a line that passes through the given point and has slope m
(3,4) m=1/2

Answer 1

y - y₁ = m(x - x₁)
y - 4 = ¹/₂(x - 3)
y - 4 = ¹/₂x - 1¹/₂
+ 4 + 4
y = ¹/₂x + 5¹/₂

Answer 2

Plug the point and the slope into point-slope form and simplify to get it in slope-intercept form.


`\sf~y-y_1=m(x-x_1)`

Where y1 is the y-value of the point, x1 is the x-value, and 'm' is the slope.


`\sf~y-4=(1)/(2)(x-3)`

Distribute 1/2:


`\sf~y-4=(1)/(2)x-1.5`

Add 4 to both sides:


`\boxed{\sf~y=(1)/(2)x+2.5}`

or


`\boxed{\sf~y=(1)/(2)x+2(1)/(2)}`