Question

2x-8/x^2
what is the range of this function ?

Answer 1

The function is continuous for
`x>0`. It goes to
`-\infty` when
`x\to0` and it goes to
`+\infty` when
`x\to+\infty` hence its range is
`\Bbb{R}=(-\infty,+\infty)`