Question

I need to know the surface area for all of them.

Answer 1

`253.30\:yd²`

1) In this triangular pyramid, we can see that there are some measurements. Let's enlist them:

Slant height: 14.866 yd

Height=14

height of the base: 8.66

length of the base side: 10 yd

2) So, let's find the area of that pyramid:

`\begin{gathered} Base\:Area=(a^2√(3))/(4)=(10^2√(3))/(4)=25√(3) \\ Lateral\:Area=3*((10*14)/(2))\Rightarrow210 \\ TSA=210+25√(3)\approx253.30\:yd² \end{gathered}`

Note that we have used the base times height time 1/2 for the3 lateral triangle area the base triangle is an equilateral one.