Question

How do I divide complex numbers?
`((6 - i))/((5 + 4i))`

Answer 1

`\begin{gathered} (6-i)/(5+4i) \\ \\ \text{Multiply by the conjugate} \\ (6-i)/(5+4i)\cdot(5-4i)/(5-4i) \\ (30-24i-5i+4i^2)/(25-20i+20i-16i^2) \\ (30-29i+4i^2)/(25-16i^2) \\ \\ (30-29i+4(-1))/(25-16(-1)) \\ \\ (30-4-29i)/(25+16)=(26-29i)/(41) \end{gathered}`