Question

Write the equation of the line in point-slope form perpendicular to y= -3x+6 passing through the point(-9, -4)

Answer 1

y + 4 = 1/3(x + 9)

Explanations:

The formula for finding the equation of a line perpenicular to another line and passing through a point (x1, y1) is expressed as

`y-y_1=-(1)/(m)(x-x_1)`

where:

• m is sthe ,slope of the given line

,

• (x1, y1) is the ,point on the line

Determine the slope of the given line

Given the equation y = -3x + 6, the slope of the line is -3

Substitute the slope and the given point into the formula as shown:

`\begin{gathered} y-(-4)=(-1)/(-3)(x-(-9)) \\ y+4=(1)/(3)(x+9) \\ \end{gathered}`

Hence the required equation in point-slope form is y + 4 = 1/3(x + 9)