Question

Marty ate 4/6 of his pizza and Luis ate 5/6 of his pizza. Marty ate more than Luis. How is that possible?

Answer 1

If Luis had a smaller pizza with a diameter of 5 inches, and Marty ate a larger pizza with a diameter of 15 inches, Marty would eat more than Luis.

First, we can find the areas of the pizzas.

Luis's:


`\sf~A=\pi\!\!~r^2`

Plug in what we know and simplify:


`\sf~A=(3.14)(5)^2`


`\sf~A=(3.14)(25)`


`\sf~A=(78.5)`

Divide by 6 to see how big each slice is.


`\sf78.5/6\approx13.08`

Multiply by 5 to find out how much pizza Luis ate total:


`\sf13.08*5=65.4`

So Luis ate approximately 65.4 square inches of pizza.

Now let's find out how much Marty ate.


`\sf~A=\pi\!\!~r^2`

Plug in what we know and simplify:


`\sf~A=(3.14)(15)^2`


`\sf~A=(3.14)(225)`


`\sf~A=(706.5)`

Divide by 6 to see how big each slice is.


`\sf78.5/6=117.75`

Multiply by 5 to find out how much pizza Marty ate total:


`\sf117.75*5=588.75`

So Marty ate 588.75 square inches of pizza, which is more than what Luis ate, 65.4 square inches.