Question

How would you find the zeros of the function by rewriting the function in intercept form? Ex: y=x^2-12x+32

Answer 1

The way i do it is factor x^2-12x+32 into (x-8)(x-4) then set each of those to zero which would look like 0=x-8 and 0=x-4. Then solve each equation and your answers would be x=8 and x=4

Answer 2

The zeros are x=4, 8

Explanation:

We have been given the function y=x^2-12x+32.

Let us write this in intercept form by factoring the given function.

We can factor it by AC method.

We can write the middle term -12x = -8x-4x

`y=x^2-12x+32\\y=x^2-8x-4x+32\\\text{Now we take GCF}\\\\y=x(x-8)-4(x-8)\\\\y=(x-8)(x-4)`

Now, in order to find the zeros, we have

`(x-8)(x-4)=0\\\\x=4,8`

Therefore, the zeros are x=4, 8