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If ƒ(x) varies directly with x and ƒ(x) = 32 when x = -8, then what is ƒ(x) when x = 4? A. -12 B. -1 C. -16 D. -8
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If ƒ(x) varies directly with x and ƒ(x) = 32 when x = -8, then what is ƒ(x) when x = 4?

A. -12
B. -1
C. -16
D. -8

User Serhii Smirnov
by
7.0k points

1 Answer

1 vote

f(x)=kx\\ 32=-8k\\ k=-4\\ f(x)=-4x\\\\ f(4)=-4\cdot4=-16
User Rashanna
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6.3k points
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