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Graph the parabola Y = X^2 + 6x +13 Play five points on a parabola the vertex two points to the left of the vertex and two points to the right of the vertex then click on the graph a function button

Graph the parabola Y = X^2 + 6x +13 Play five points on a parabola the vertex two-example-1
User Vineet Ravi
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1 Answer

24 votes
24 votes

Given:


y=x^2+6x+13

To plot 5 points on the parabola:

The given equation can be written as,


\begin{gathered} y=x^2+6x++3^2-3^2+13 \\ y=(x+3)^2-9+13 \\ y=(x+3)^2+4 \end{gathered}

Therefore, the vertex of the parabola is (-3, 4).

Put x=-2, we get y=5. So, the point is (-2, 5).

Put x=-1, we get y=8. So, the point is (-1, 8).

Put x=-4, we get y=5. So, the point is (-4, 5).

Put x=-5, we get y=8. So, the point is (-5, 8).

So, the graph is,

Graph the parabola Y = X^2 + 6x +13 Play five points on a parabola the vertex two-example-1
User DavidRguez
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3.1k points