Question

Two great structures are described below. What is thedifference, in square feet, between the visible surface area ofthe Great Pyramid and the first tower of the World TradeCenter? (Hint: The bottom side is not visible for eitherstructure.)On September 11, 2001,The Great Pyramid ofterrorists crashed planesGiza, built around 2550into the World TradeB.C., has a square baseCenter Twin Towers. Thewith a length of 756 feet,first tower was aand the distance fromrectangular prism with athe middle of any basesquare base whose sidesside to the top is 612 feet.were 208 feet long. Thetower was 1,368 feet tall.Your answer

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

Great Pyramid

square base:

length = 756 ft

slant height (l) = 612 ft

surface area (ft²) = ?

Tower World Trade Center

square base (rectangular prism)

length = 208 ft

height = 1368 ft

surface area (ft²) = ?

Step 02:

Great Pyramid

surface area:

Sp = B + 1/2 Pl

B = 756 ft * 756 ft = 571536 ft²

Pl = 4 * (756ft) * 612 ft = 1850688 ft²

Sp = 571536 ft² + 1/2 (1850688 ft²) = 1496880 ft²

No botton side:

Sp = 1850688 ft²

Tower World Trade Center

surface area:

St = 2 lw + 2 wh + 2 lh

l = w

St = 2 lw + 2 wh + 2 lh

St = 2 (208 ft*208 ft) + 2 (208 ft*1368 ft) + 2 (208 ft*1368 ft)

St = 1224704 ft²

No botton side:

Sp =

Sp - St = 272176 ft²

The answer is:

The difference (surface area) between the two structures is 272176 ft²