Question

Kerosene is supplied to a tap from a tank in which the kerosene level is 1.5 m above the tap. If the density of kerosene is 800 kg/m3. Calculate pressure of the kerosene at the tap.

Answer 1

`\begin{equation*} 11,760\text{ }N\/m^2 \end{equation*}`

Step-by-step explanation

To find the pressure of the kerosene at the tap, we have to apply the relationship between pressure and density:

`P=\rho *g*h`

where ρ = density

g = acceleration due to gravity = 9.8 m/s^2

h = height

Therefore, the pressure of the kerosene at the tap is:

`\begin{gathered} P=800*9.8*1.5 \\ P=11,760\text{ }N\/m^2 \end{gathered}`

That is the answer.