Question

-x2 + x-1=0

find the discriminant of each quadratic equation then state the number and type of solution

Answer 1

ax² + bx + c = 0
-x² + x - 1= 0
x = -b +/- √b² - 4ac
2a
x = -1 +/- √1² - 4(-1)(-1)
2(-1)
x = -1 +/- √1 - 4
-2
x = -1 +/- √-3
-2
x = -1 +/- (-1.732050808)
-2
x = -1 - 1.732050808 x = -1 + 1.732050808
-2 -2
x = -2.732050808 x = 0.732050808
-2 -2
x = 1.366025404 x = 0.366025404

Answer 2

-x^2 + x-1=0 divide by (-)

x^2-x+1=0

x=1/2(+-) root of (1/2)^2-1

x=1/2(+-) root of (1/4)-1

x=1/2(+-) root of (1/4)-1

x=1/2(+-) root of (1/4)-((4*1)/4)

x=1/2(+-) root of (-3/4)

which has not answers, because we can not take a root of negatives numbers