Question

Stuck on question 1, can anyone help???

Answer 1

so square root of 25=a
a could be 5
cube of a=b
5^3=125=b
125-25=c=100
c=100
squareroot of 100=d=10
10+39=e=49
square root of 49=7
F=7


a=5
b=125
c=100
d=10
e=49
f=7

Answer 2

'A' is the square root of 25. That's 5, so take A=5 with you
as you go to the next step.

B is A³. A³ means (A x A x A). We know that 'A' is 5, so 'B' is (5x 5 x 5) = 125 .
Take B=125 with you to the next step.

'C' is B - 25. We know that 'B' is 125. So C = (125 - 25) = 100 .
Take C=100 with you to the next step.

'D' is the square root of 'C'. We know that C=100, so D = √100 .
The square root of 100 is 10, so D=10.
Take D=10 with you to the next step .

'E' is D+39. We know that D=10. So E=(10+39) = 49 .
Take E=49 with you to the last step.

'F' is the square root of 'E'. We know that E=49.