50 mm cylinder; to be filled with 43 1/5 mm of liquid mixture; 2/3 of water; 1/3 of unknown;
answer 1) 2/3 of water of a total of 43 1/5mm; that means (43.2) multiplied by 2/3: (43.2)x2/3 = 86.4/3 = 28.8 mm of water
1/3 of unknown of a total of 43.2mm; that means (43.2) muliplied by 1/3: (43.2)x1/3 = 43.2/3 = 14.4 mm of unknown
answer 2) If the total quantity of the original mixture is 43.2 mm, and it has to be divided evenly into 4 cylinders, they have to put 43.2/4 on each cylinder, 43.2/4 = 10.8 mm
answer 3) Each of the 4 cylinders have 10.8 mm of liquid, if they take the firs one and transfer 2 mm to the second cylinder, the first sylinder will be left with only 10.8 - 2 = 8.8 mm; then they take the first cylinder and transfer 4 mm to the third cylinder, so the first cylinder is left with 8.8-4 = 4.8mm of liquid; finally thay should transfer 6 mm from the first cylinder to the fouth... BUT THE FIRST CYLINDER ONLY HAS 4.8 mm OF LIQUID... It does not make sence